What is the domain of sqrt((x+2)/(x^2-9)) ?

The domain of sqrt((x+2)/(x^2-9)) is -3 3

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domain of sqrt((x+2)/(x^2-9))

domain

\frac{x + 2}{x ^{2} - 9}

- 3 < x \leq - 2 or x > 3

Interval Notation

(- 3, - 2] \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

- 3 < x \leq - 2 or x > 3

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 3 < x \leq - 2 or x > 3

f (x) = \frac{3 - x}{x ^{2} - 4}

f (x) = \frac{2 x - 1}{2 - x}

f (x) = e^{2 x} - 3

\frac{2}{1 - cos ( x )}

f (x) = \frac{- x + 10}{x ^{3}}

What is the domain of sqrt((x+2)/(x^2-9)) ?
The domain of sqrt((x+2)/(x^2-9)) is -3<x<=-2\lor x>3