What is the domain of (sqrt(5-2x))/(-7x) ?

The domain of (sqrt(5-2x))/(-7x) is x<0\lor 0<x<= 5/2

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domain of (sqrt(5-2x))/(-7x)

domain

\frac{5 - 2 x}{- 7 x}

x < 0 or 0 < x \leq \frac{5}{2}

Interval Notation

(- \infty, 0) \cup (0, \frac{5}{2}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{5}{2}

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x < 0 or 0 < x \leq \frac{5}{2}

f (x) = 9 x - 1620

- \frac{2}{3} x - 4

f (x) = 5 x^{4} - 13

f (x) = \frac{2}{- x ^{2} + 4 x + 5}

f (x) = \frac{x}{8}

What is the domain of (sqrt(5-2x))/(-7x) ?
The domain of (sqrt(5-2x))/(-7x) is x<0\lor 0<x<= 5/2