What is the domain of y=(x^2+x)/(x+1) ?

The domain of y=(x^2+x)/(x+1) is x -1

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domain of y=(x^2+x)/(x+1)

domain

y = \frac{x ^{2} + x}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = x - 2 - \frac{1}{3 - x}

ln (\frac{x}{x - 3})

f (x) = sin (2 x)

f (x) = 6 x - 1248

\frac{2 x - 6}{5}

What is the domain of y=(x^2+x)/(x+1) ?
The domain of y=(x^2+x)/(x+1) is x<-1\lor x>-1