What is the domain of f(x)= x/(sqrt(x^2+2x-8)) ?

The domain of f(x)= x/(sqrt(x^2+2x-8)) is x 2

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domain of f(x)= x/(sqrt(x^2+2x-8))

domain

f (x) = \frac{x}{x ^{2} + 2 x - 8}

x < - 4 or x > 2

Interval Notation

(- \infty, - 4) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 2

Find undefined (singularity) points:

x = 2, x = - 4

Combine real regions and undefined points for final function domain

x < - 4 or x > 2

f (x) = \frac{20 - 4 x}{2}

y = \frac{2 x + 14}{x ^{2} - 49}

f (x) = \frac{x + 1}{x ^{2} - x - 2}

f (x) = \frac{x + 6}{x ^{2} - 4}

(x - 1)^{3}

What is the domain of f(x)= x/(sqrt(x^2+2x-8)) ?
The domain of f(x)= x/(sqrt(x^2+2x-8)) is x<-4\lor x>2