What is the domain of f(x)=sqrt(t^2-4) ?

The domain of f(x)=sqrt(t^2-4) is t = 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(t^2-4)

domain

f (x) = t^{2} - 4

t \leq - 2 or t \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

t \leq - 2 or t \geq 2

The function domain

t \leq - 2 or t \geq 2

lo g_{2} (\frac{2}{3} x - 4)

f (x) = - x - 9

f (x) = \frac{x - 1}{x - 2}

f (x, y) = x

y = \frac{x - 5}{x ^{2} - 4 x}

What is the domain of f(x)=sqrt(t^2-4) ?
The domain of f(x)=sqrt(t^2-4) is t<=-2\lor t>= 2