What is the domain of f(x)=(2x)/(sqrt(5-2x)) ?

The domain of f(x)=(2x)/(sqrt(5-2x)) is x< 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(2x)/(sqrt(5-2x))

domain

f (x) = \frac{2 x}{5 - 2 x}

x < \frac{5}{2}

Interval Notation

(- \infty, \frac{5}{2})

Solution steps

Find non-negative values for radicals:

x \leq \frac{5}{2}

Find undefined (singularity) points:

x = \frac{5}{2}

Combine real regions and undefined points for final function domain

x < \frac{5}{2}

f (x) = \frac{( 4 x ^{2} + 4 )}{( 2 x ^{2} - 8 )}

y = \frac{x + 3}{12 - x ^{2} - 25}

f (x) = \frac{x - 1}{x ^{2} - 1}

f (x) = lo g_{10} (∣ x ∣)

What is the domain of f(x)=(2x)/(sqrt(5-2x)) ?
The domain of f(x)=(2x)/(sqrt(5-2x)) is x< 5/2