What is the domain of f(x)=(8x^2-10x-3)/(2x^2-9x+9) ?

The domain of f(x)=(8x^2-10x-3)/(2x^2-9x+9) is x 3

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domain of f(x)=(8x^2-10x-3)/(2x^2-9x+9)

domain

f (x) = \frac{8 x ^{2} - 10 x - 3}{2 x ^{2} - 9 x + 9}

x < \frac{3}{2} or \frac{3}{2} < x < 3 or x > 3

Interval Notation

(- \infty, \frac{3}{2}) \cup (\frac{3}{2}, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = \frac{3}{2}

The function domain

x < \frac{3}{2} or \frac{3}{2} < x < 3 or x > 3

f (x) = \frac{( x ^{2} + 3 )}{x + 3}

y = - 2 x - 7

f (x) = (x - 1) (x + 2)

y = x - 5 - 1

f (x) = \frac{2}{1 + x}

What is the domain of f(x)=(8x^2-10x-3)/(2x^2-9x+9) ?
The domain of f(x)=(8x^2-10x-3)/(2x^2-9x+9) is x< 3/2 \lor 3/2 <x<3\lor x>3