What is the domain of f(x)= 5/(x^2-x) ?

The domain of f(x)= 5/(x^2-x) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 5/(x^2-x)

domain

f (x) = \frac{5}{x ^{2} - x}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = 0

The function domain

x < 0 or 0 < x < 1 or x > 1

f (x) = - 3 t

f (x) = lo g_{2} (x - 3) + 1

f (x) = f (x) = \frac{( x ^{2} + 16 )}{( x ^{2} - 9 )}

f (x) = \frac{1}{4} x

f (x) = x - 1 - 1

What is the domain of f(x)= 5/(x^2-x) ?
The domain of f(x)= 5/(x^2-x) is x<0\lor 0<x<1\lor x>1