What is the domain of f(x)=(3x-1)/(4x+1) ?

The domain of f(x)=(3x-1)/(4x+1) is x -1/4

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domain of f(x)=(3x-1)/(4x+1)

domain

f (x) = \frac{3 x - 1}{4 x + 1}

x < - \frac{1}{4} or x > - \frac{1}{4}

Interval Notation

(- \infty, - \frac{1}{4}) \cup (- \frac{1}{4}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{1}{4}

The function domain

x < - \frac{1}{4} or x > - \frac{1}{4}

f (x) = \frac{2 x + 4}{x ^{2} - 5 x + 6}

f (x) = \frac{2 x - 5}{3 - 2 x}

f (x) = 2 x^{2} + 5 x - 10

y = \frac{( x ^{2} - 16 )}{( x ^{2} - x - 6 )}

f (x) = - x^{2} + x

What is the domain of f(x)=(3x-1)/(4x+1) ?
The domain of f(x)=(3x-1)/(4x+1) is x<-1/4 \lor x>-1/4