What is the domain of f(x)=sqrt(x-x^2) ?

The domain of f(x)=sqrt(x-x^2) is 0<= x<= 1

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domain of f(x)=sqrt(x-x^2)

domain

f (x) = x - x^{2}

0 \leq x \leq 1

Interval Notation

[0, 1]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 1

The function domain

0 \leq x \leq 1

y = \frac{- 2}{x - 5}

f (x) = \frac{x}{2 x - [ x ]}

x^{2} - x - 6

- (x + 2)^{5} (x - 4)^{4}

b^{x}

What is the domain of f(x)=sqrt(x-x^2) ?
The domain of f(x)=sqrt(x-x^2) is 0<= x<= 1