What is the domain of y=-log_{2}(3(x-2))+4 ?

The domain of y=-log_{2}(3(x-2))+4 is x>2

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domain of y=-log_{2}(3(x-2))+4

domain

y = - lo g_{2} (3 (x - 2)) + 4

x > 2

Interval Notation

(2, \infty)

Solution steps

Find positive values for logs:

x > 2

The function domain

x > 2

25 - 5^{x}

f (x) = - 5 x + 3, - 2 \leq x \leq 4

f (x) = 12 x^{3} - 5 x^{2} - 11 x + 6

f (x) = \frac{2}{3} + \frac{4 - x ^{2}}{x - 3}

f (x) = \frac{7}{x + 1}

What is the domain of y=-log_{2}(3(x-2))+4 ?
The domain of y=-log_{2}(3(x-2))+4 is x>2