What is the domain of sqrt(x^2-4)+sqrt(x^2+5x+6) ?

The domain of sqrt(x^2-4)+sqrt(x^2+5x+6) is x = 2

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domain of sqrt(x^2-4)+sqrt(x^2+5x+6)

domain

x^{2} - 4 + x^{2} + 5 x + 6

x \leq - 3 or x = - 2 or x \geq 2

Interval Notation

(- \infty, - 3] \cup x = - 2 \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x = - 2 or x \geq 2

The function domain

x \leq - 3 or x = - 2 or x \geq 2

\frac{x + 1}{x ^{2} - 2 x + 1}

f (t) = 4 - t^{2}

x^{2} - 4 x + 3

6 x - 6

f (x) = ∣ x ∣ + ∣ x - 1 ∣ + ∣ x - 2 ∣

What is the domain of sqrt(x^2-4)+sqrt(x^2+5x+6) ?
The domain of sqrt(x^2-4)+sqrt(x^2+5x+6) is x<=-3\lor x=-2\lor x>= 2