What is the domain of g(x)=(x+4)/(x^2-9) ?

The domain of g(x)=(x+4)/(x^2-9) is x 3

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domain of g(x)=(x+4)/(x^2-9)

domain

g (x) = \frac{x + 4}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

y = x^{2} - 4 x - 5

y = 2 x^{2} - 8 x + 8

5 \cdot (\frac{1}{4})^{x}

f (x) = \frac{x - 3}{3 x + 2}

f (x) = 2 - 0.4 x

What is the domain of g(x)=(x+4)/(x^2-9) ?
The domain of g(x)=(x+4)/(x^2-9) is x<-3\lor-3<x<3\lor x>3