What is the domain of f(x)= x/(x^3+8) ?

The domain of f(x)= x/(x^3+8) is x -2

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domain of f(x)= x/(x^3+8)

domain

f (x) = \frac{x}{x ^{3} + 8}

x < - 2 or x > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2

The function domain

x < - 2 or x > - 2

f (x) = \frac{6 x - 2 - 3}{x ^{2} + 1}

f (x) = \frac{7}{7 x}

f (x) = \frac{17 x - 6}{6 x + 4}

1 - ∣ x ∣

f (x) = arccos (x^{2} - 1)

What is the domain of f(x)= x/(x^3+8) ?
The domain of f(x)= x/(x^3+8) is x<-2\lor x>-2