What is the domain of f(x)=sqrt(arccos(x^2-1)) ?

The domain of f(x)=sqrt(arccos(x^2-1)) is -sqrt(2)<= x<= sqrt(2)

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domain of f(x)=sqrt(arccos(x^2-1))

domain

f (x) = arccos (x^{2} - 1)

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

f (x) = \frac{x - 8}{3 x - 4}

2 x^{3} + 2 x - 1 - (2 x^{2} - 5 x - 6)

f (x) = - (x + 5)^{2} - 4

y, y < 2 x

(1 - 2 x) - (3 - 2 x - x^{2})

What is the domain of f(x)=sqrt(arccos(x^2-1)) ?
The domain of f(x)=sqrt(arccos(x^2-1)) is -sqrt(2)<= x<= sqrt(2)