What is the domain of (sqrt(1-2x))-(sqrt(3-2x-x^2)) ?

The domain of (sqrt(1-2x))-(sqrt(3-2x-x^2)) is -3<= x<= 1/2

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domain of (sqrt(1-2x))-(sqrt(3-2x-x^2))

domain

(1 - 2 x) - (3 - 2 x - x^{2})

- 3 \leq x \leq \frac{1}{2}

Interval Notation

[- 3, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

- 3 \leq x \leq \frac{1}{2}

The function domain

- 3 \leq x \leq \frac{1}{2}

f (x) = 5 x + 5

\frac{2}{x ^{2} - 6 x + 8}

\frac{2 x - 7}{3}

\frac{x + 1}{2 x - 3}

(x + 1)^{2} + 2

What is the domain of (sqrt(1-2x))-(sqrt(3-2x-x^2)) ?
The domain of (sqrt(1-2x))-(sqrt(3-2x-x^2)) is -3<= x<= 1/2