What is the domain of sqrt((x+1)^2)+2 ?

The domain of sqrt((x+1)^2)+2 is -infinity <x<infinity

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domain of sqrt((x+1)^2)+2

domain

(x + 1)^{2} + 2

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{2}{- x ^{2} + 4 x + 5}

ln^{\frac{1}{x}} (x)

f (x) = 1 + x + 2

4 \cdot x + 3

f (x) = 2 + ln (x)

What is the domain of sqrt((x+1)^2)+2 ?
The domain of sqrt((x+1)^2)+2 is -infinity <x<infinity