What is the domain of f(x)=1+sqrt(x+2) ?

The domain of f(x)=1+sqrt(x+2) is x>=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=1+sqrt(x+2)

domain

f (x) = 1 + x + 2

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

4 \cdot x + 3

f (x) = 2 + ln (x)

y = \frac{x - 7}{x + 12}

\frac{x ^{7}}{3} + 3

f (x) = - \frac{x}{- x - 2}

What is the domain of f(x)=1+sqrt(x+2) ?
The domain of f(x)=1+sqrt(x+2) is x>=-2