What is the domain of f(x)=sqrt(2+ln(x)) ?

The domain of f(x)=sqrt(2+ln(x)) is x>= 1/(e^2)

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domain of f(x)=sqrt(2+ln(x))

domain

f (x) = 2 + ln (x)

x \geq \frac{1}{e ^{2}}

Interval Notation

[\frac{1}{e ^{2}}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{e ^{2}}

The function domain

x \geq \frac{1}{e ^{2}}

y = \frac{x - 7}{x + 12}

\frac{x ^{7}}{3} + 3

f (x) = - \frac{x}{- x - 2}

f (x) = \frac{1}{2 x ^{2} - 8}

\frac{x ^{2} - 8 x + 15}{x + 3}

What is the domain of f(x)=sqrt(2+ln(x)) ?
The domain of f(x)=sqrt(2+ln(x)) is x>= 1/(e^2)