What is the domain of f(x)= 1/(sqrt(x^2-16)) ?

The domain of f(x)= 1/(sqrt(x^2-16)) is x 4

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domain of f(x)= 1/(sqrt(x^2-16))

domain

f (x) = \frac{1}{x ^{2} - 16}

x < - 4 or x > 4

Interval Notation

(- \infty, - 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

Find undefined (singularity) points:

x = 4, x = - 4

Combine real regions and undefined points for final function domain

x < - 4 or x > 4

f (x) = \frac{x + 3}{x ^{2} - 36}

f (x) = lo g_{10} (2 x - 12)

f (x) = 1.5

f (x) = 1 + \frac{1}{x} - \frac{x}{x - 1}

What is the domain of f(x)= 1/(sqrt(x^2-16)) ?
The domain of f(x)= 1/(sqrt(x^2-16)) is x<-4\lor x>4