What is the domain of f(x)=\sqrt[3]{y/(y-4)} ?

The domain of f(x)=\sqrt[3]{y/(y-4)} is y 4

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domain of f(x)=\sqrt[3]{y/(y-4)}

domain

y < 4 or y > 4

Interval Notation

(- \infty, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

y = 4

The function domain

y < 4 or y > 4

f (x) = \frac{x + 3}{x ^{2} - 36}

f (x) = lo g_{10} (2 x - 12)

f (x) = 1.5

f (x) = 1 + \frac{1}{x} - \frac{x}{x - 1}

f (x) = e^{\frac{1}{x}} x^{2} + 2 x

What is the domain of f(x)=\sqrt[3]{y/(y-4)} ?
The domain of f(x)=\sqrt[3]{y/(y-4)} is y<4\lor y>4