What is the domain of f(x)= 1/(x^2-36) ?

The domain of f(x)= 1/(x^2-36) is x 6

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domain of f(x)= 1/(x^2-36)

domain

f (x) = \frac{1}{x ^{2} - 36}

x < - 6 or - 6 < x < 6 or x > 6

Interval Notation

(- \infty, - 6) \cup (- 6, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 6

The function domain

x < - 6 or - 6 < x < 6 or x > 6

\frac{x ^{2} + 24}{6}

f (x) = \frac{2 x + 4}{x ^{2} - x - 2}

f (x) = x^{2} - 4 x + 9

f (x) = \frac{1}{x ^{2} - 8 x + 16}

y = x^{2} - x

What is the domain of f(x)= 1/(x^2-36) ?
The domain of f(x)= 1/(x^2-36) is x<-6\lor-6<x<6\lor x>6