What is the domain of f(x)= 1/(x^2-8x+16) ?

The domain of f(x)= 1/(x^2-8x+16) is x 4

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domain of f(x)= 1/(x^2-8x+16)

domain

f (x) = \frac{1}{x ^{2} - 8 x + 16}

x < 4 or x > 4

Interval Notation

(- \infty, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4

The function domain

x < 4 or x > 4

y = x^{2} - x

f (x) = - x^{2} + 2 x

f (x) = arccos (x - 3)

3 + 16 - (x - 3)^{2}

f (x) = \frac{- 2 \cdot 0}{4} + e^{0} - 13

What is the domain of f(x)= 1/(x^2-8x+16) ?
The domain of f(x)= 1/(x^2-8x+16) is x<4\lor x>4