What is the domain of f(x)=sqrt(-x^2+2x) ?

The domain of f(x)=sqrt(-x^2+2x) is 0<= x<= 2

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domain of f(x)=sqrt(-x^2+2x)

domain

f (x) = - x^{2} + 2 x

0 \leq x \leq 2

Interval Notation

[0, 2]

Solution steps

Find non-negative values for radicals:

0 \leq x \leq 2

The function domain

0 \leq x \leq 2

f (x) = arccos (x - 3)

3 + 16 - (x - 3)^{2}

f (x) = \frac{- 2 \cdot 0}{4} + e^{0} - 13

y = 5 x - 2

f (x) = - x^{2} - 2 x + 8

What is the domain of f(x)=sqrt(-x^2+2x) ?
The domain of f(x)=sqrt(-x^2+2x) is 0<= x<= 2