What is the domain of 3+sqrt(16-(x-3)^2) ?

The domain of 3+sqrt(16-(x-3)^2) is -1<= x<= 7

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domain of 3+sqrt(16-(x-3)^2)

domain

3 + 16 - (x - 3)^{2}

- 1 \leq x \leq 7

Interval Notation

[- 1, 7]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 7

The function domain

- 1 \leq x \leq 7

f (x) = \frac{- 2 \cdot 0}{4} + e^{0} - 13

y = 5 x - 2

f (x) = - x^{2} - 2 x + 8

f (x) = - 3 y - 2

\frac{3 x + 4}{x ^{2} + 7 x + 12}

What is the domain of 3+sqrt(16-(x-3)^2) ?
The domain of 3+sqrt(16-(x-3)^2) is -1<= x<= 7