What is the domain of f(x)=-sqrt(3y-2) ?

The domain of f(x)=-sqrt(3y-2) is y>= 2/3

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domain of f(x)=-sqrt(3y-2)

domain

f (x) = - 3 y - 2

y \geq \frac{2}{3}

Interval Notation

[\frac{2}{3}, \infty)

Solution steps

Find non-negative values for radicals:

y \geq \frac{2}{3}

The function domain

y \geq \frac{2}{3}

\frac{3 x + 4}{x ^{2} + 7 x + 12}

f (x) = \frac{2 - x}{ln ( x )}

f (x) = \frac{x - 6}{x ^{2} - 3 x - 18}

e^{2 x + 3}

f (x) = 2 x^{2} - 11 x + 12 + 1

What is the domain of f(x)=-sqrt(3y-2) ?
The domain of f(x)=-sqrt(3y-2) is y>= 2/3