What is the domain of f(x)=(x-6)/(x^2-3x-18) ?

The domain of f(x)=(x-6)/(x^2-3x-18) is x 6

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domain of f(x)=(x-6)/(x^2-3x-18)

domain

f (x) = \frac{x - 6}{x ^{2} - 3 x - 18}

x < - 3 or - 3 < x < 6 or x > 6

Interval Notation

(- \infty, - 3) \cup (- 3, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 3

The function domain

x < - 3 or - 3 < x < 6 or x > 6

e^{2 x + 3}

f (x) = 2 x^{2} - 11 x + 12 + 1

f (x) = ln (ln (x^{2}))

\frac{x - 5}{x ^{2} - 4 x}

lo g_{10} (x^{2} + 2 x - 3)

What is the domain of f(x)=(x-6)/(x^2-3x-18) ?
The domain of f(x)=(x-6)/(x^2-3x-18) is x<-3\lor-3<x<6\lor x>6