What is the domain of f(x)=sqrt(2x^2-11x+12)+1 ?

The domain of f(x)=sqrt(2x^2-11x+12)+1 is x = 4

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domain of f(x)=sqrt(2x^2-11x+12)+1

domain

f (x) = 2 x^{2} - 11 x + 12 + 1

x \leq \frac{3}{2} or x \geq 4

Interval Notation

(- \infty, \frac{3}{2}] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq \frac{3}{2} or x \geq 4

The function domain

x \leq \frac{3}{2} or x \geq 4

f (x) = ln (ln (x^{2}))

\frac{x - 5}{x ^{2} - 4 x}

lo g_{10} (x^{2} + 2 x - 3)

f (x) = x^{3} - 6

f (x) = x - 2 + 4

What is the domain of f(x)=sqrt(2x^2-11x+12)+1 ?
The domain of f(x)=sqrt(2x^2-11x+12)+1 is x<= 3/2 \lor x>= 4