What is the domain of f(x)=log_{10}(2x-1) ?

The domain of f(x)=log_{10}(2x-1) is x> 1/2

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domain of f(x)=log_{10}(2x-1)

domain

f (x) = lo g_{10} (2 x - 1)

x > \frac{1}{2}

Interval Notation

(\frac{1}{2}, \infty)

Solution steps

Find positive values for logs:

x > \frac{1}{2}

The function domain

x > \frac{1}{2}

f (x) = \frac{x - 13}{x ^{2} - x - 6}

f (x) = e^{- 6 x}

\frac{1}{4} x

\frac{2 x}{x ^{2} - 9}

f (x) = 1 x^{3} + 4 x^{2} + 4 x + d

What is the domain of f(x)=log_{10}(2x-1) ?
The domain of f(x)=log_{10}(2x-1) is x> 1/2