What is the domain of f(x)=log_{e}(x^2-1) ?

The domain of f(x)=log_{e}(x^2-1) is x 1

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domain of f(x)=log_{e}(x^2-1)

domain

f (x) = lo g_{e} (x^{2} - 1)

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

f (x) = \frac{1}{- x ^{2} + 6 x}

\frac{3 - x + 1}{x + 1 - 1}

f (x) = ln (x^{2} + 3 x)

f (x) = 0. 3^{x}

y = \frac{6}{x ( x + 9 )}

What is the domain of f(x)=log_{e}(x^2-1) ?
The domain of f(x)=log_{e}(x^2-1) is x<-1\lor x>1