What is the domain of f(x)= pi/2-arcsin(2x) ?

The domain of f(x)= pi/2-arcsin(2x) is -1/2 <= x<= 1/2

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domain of f(x)= pi/2-arcsin(2x)

domain

f (x) = \frac{π}{2} - arcsin (2 x)

- \frac{1}{2} \leq x \leq \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \frac{1}{2}]

Solution steps

Find known functions domain restrictions:

- \frac{1}{2} \leq x \leq \frac{1}{2}

The function domain

- \frac{1}{2} \leq x \leq \frac{1}{2}

f (x) = 2 sin (x) + cos (2 x)

f (x) = x \cdot 4 - x^{2}

f (x) = \frac{x + 3}{ln ( x - 1 )}

\frac{4}{x + 1}

f (x) = - x^{2} + 2 x + 1

What is the domain of f(x)= pi/2-arcsin(2x) ?
The domain of f(x)= pi/2-arcsin(2x) is -1/2 <= x<= 1/2