What is the domain of f(x)=(sqrt(x^2-4))/(x^2-2x) ?

The domain of f(x)=(sqrt(x^2-4))/(x^2-2x) is x 2

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domain of f(x)=(sqrt(x^2-4))/(x^2-2x)

domain

f (x) = \frac{x ^{2} - 4}{x ^{2} - 2 x}

x \leq - 2 or x > 2

Interval Notation

(- \infty, - 2] \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

Find undefined (singularity) points:

x = 2, x = 0

Combine real regions and undefined points for final function domain

x \leq - 2 or x > 2

\frac{x - 1}{x}

y = lo g_{10} (3 x - 4)

f (x) = 5 x^{3} - 5 x + 1

x^{4} - 4 x^{3} + \frac{14}{3} x^{2} - \frac{9}{7} x + 2

What is the domain of f(x)=(sqrt(x^2-4))/(x^2-2x) ?
The domain of f(x)=(sqrt(x^2-4))/(x^2-2x) is x<=-2\lor x>2