What is the domain of sqrt(2x-1)-3 ?

The domain of sqrt(2x-1)-3 is x>= 1/2

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domain of sqrt(2x-1)-3

domain

2 x - 1 - 3

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

The function domain

x \geq \frac{1}{2}

f (x) = \frac{1}{- x ^{2} + 3 x}

f (x) = ∣ 3 x + 6 ∣

f (x) = ln (x) + lo g_{3} (3 - 2 x)

y = 2 x + 16

\frac{x ^{4} + 1}{x ^{2}}