What is the domain of f(x)= x/(x^2+4x) ?

The domain of f(x)= x/(x^2+4x) is x 0

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domain of f(x)= x/(x^2+4x)

domain

f (x) = \frac{x}{x ^{2} + 4 x}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

f (x) = - 2 x^{2} + 3 x - 3

f (x) = arcsin (ln (2 x))

f (x) = lo g_{10} (6) + 2 x

f (x) = \frac{1}{x ^{2} - 1} - 3

\frac{x ^{2} - 9}{x ^{2} - 4}

What is the domain of f(x)= x/(x^2+4x) ?
The domain of f(x)= x/(x^2+4x) is x<-4\lor-4<x<0\lor x>0