What is the domain of f(x)=\sqrt[3]{2x+1/4} ?

The domain of f(x)=\sqrt[3]{2x+1/4} is -infinity <x<infinity

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domain of f(x)=\sqrt[3]{2x+1/4}

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = t - 5

f (x) = 2 x^{2} - x - 6 + 2

f (x) = \frac{x}{ln ( x )}

f (x) = \frac{( - 1 )}{x}

f (x) = 5 - 2 x + 4

What is the domain of f(x)=\sqrt[3]{2x+1/4} ?
The domain of f(x)=\sqrt[3]{2x+1/4} is -infinity <x<infinity