What is the domain of f(x)=log_{7}(3x-2) ?

The domain of f(x)=log_{7}(3x-2) is x> 2/3

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domain of f(x)=log_{7}(3x-2)

domain

f (x) = lo g_{7} (3 x - 2)

x > \frac{2}{3}

Interval Notation

(\frac{2}{3}, \infty)

Solution steps

Find positive values for logs:

x > \frac{2}{3}

The function domain

x > \frac{2}{3}

f (x) = \frac{x ^{2}}{x ^{2} + 16}

f (x) = 9 x - 3

5.75 cos (\frac{π}{3} t) + 7.88

f (x) = - x^{2} + 7 x

y + 4 = x^{\frac{2}{3}}

What is the domain of f(x)=log_{7}(3x-2) ?
The domain of f(x)=log_{7}(3x-2) is x> 2/3