What is the domain of f(x)=sqrt(9x-3) ?

The domain of f(x)=sqrt(9x-3) is x>= 1/3

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domain of f(x)=sqrt(9x-3)

domain

f (x) = 9 x - 3

x \geq \frac{1}{3}

Interval Notation

[\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{3}

The function domain

x \geq \frac{1}{3}

5.75 cos (\frac{π}{3} t) + 7.88

f (x) = - x^{2} + 7 x

y + 4 = x^{\frac{2}{3}}

\frac{x ^{2} - 3 x + 2}{x ^{2} + 7 x + 12}

f (x) = \frac{4}{5} x + 2

What is the domain of f(x)=sqrt(9x-3) ?
The domain of f(x)=sqrt(9x-3) is x>= 1/3