What is the domain of sqrt(\sqrt{x)-1}-1 ?

The domain of sqrt(\sqrt{x)-1}-1 is x>= 1

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domain of sqrt(\sqrt{x)-1}-1

domain

x - 1 - 1

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = 6 x + 2

\frac{8}{x - 3}

7 + 4 t + 5 (11 - 3 t)

f (x) = \frac{1}{2} cos (2 x - \frac{π}{3})

f (x) = - 6 x^{2} - 14 x - 4

What is the domain of sqrt(\sqrt{x)-1}-1 ?
The domain of sqrt(\sqrt{x)-1}-1 is x>= 1