What is the domain of f(x)=sqrt(6x+2) ?

The domain of f(x)=sqrt(6x+2) is x>=-1/3

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domain of f(x)=sqrt(6x+2)

domain

f (x) = 6 x + 2

x \geq - \frac{1}{3}

Interval Notation

[- \frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{3}

The function domain

x \geq - \frac{1}{3}

\frac{8}{x - 3}

7 + 4 t + 5 (11 - 3 t)

f (x) = \frac{1}{2} cos (2 x - \frac{π}{3})

f (x) = - 6 x^{2} - 14 x - 4

\frac{1}{x ^{2} + 2 x - 3}

What is the domain of f(x)=sqrt(6x+2) ?
The domain of f(x)=sqrt(6x+2) is x>=-1/3