What is the domain of 1/(x^2+2x-3) ?

The domain of 1/(x^2+2x-3) is x 1

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domain of 1/(x^2+2x-3)

domain

\frac{1}{x ^{2} + 2 x - 3}

x < - 3 or - 3 < x < 1 or x > 1

Interval Notation

(- \infty, - 3) \cup (- 3, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 3

The function domain

x < - 3 or - 3 < x < 1 or x > 1

\frac{x ^{2} + x - 2}{x ^{2} - x - 2}

f (x) = t - 5

y = - (x - 1)^{3} (x + 3)^{2}

y = 5^{x^{2} - 4 x - 2}

f (x) = t - 1

What is the domain of 1/(x^2+2x-3) ?
The domain of 1/(x^2+2x-3) is x<-3\lor-3<x<1\lor x>1