What is the domain of f(x)=sqrt(t-1) ?

The domain of f(x)=sqrt(t-1) is t>= 1

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domain of f(x)=sqrt(t-1)

domain

f (x) = t - 1

t \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 1

The function domain

t \geq 1

y = \frac{1}{x ^{2} - 2 x - 8}

\frac{5}{( x + 1 ) ^{2}}

f (x) = \frac{1}{x 1 + x}

x^{2} - 10 ln (x)

f (x) = \frac{x ^{2} - 2}{x ^{2} + 3}