What is the domain of y= 1/(x^2-2x-8) ?

The domain of y= 1/(x^2-2x-8) is x 4

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domain of y= 1/(x^2-2x-8)

domain

y = \frac{1}{x ^{2} - 2 x - 8}

x < - 2 or - 2 < x < 4 or x > 4

Interval Notation

(- \infty, - 2) \cup (- 2, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 2

The function domain

x < - 2 or - 2 < x < 4 or x > 4

\frac{5}{( x + 1 ) ^{2}}

f (x) = \frac{1}{x 1 + x}

x^{2} - 10 ln (x)

f (x) = \frac{x ^{2} - 2}{x ^{2} + 3}

\frac{x ^{2} + 2 x - 3}{x ^{2} - 1}

What is the domain of y= 1/(x^2-2x-8) ?
The domain of y= 1/(x^2-2x-8) is x<-2\lor-2<x<4\lor x>4