What is the domain of f(x)=(sqrt(x+1))/(sqrt(x-1)) ?

The domain of f(x)=(sqrt(x+1))/(sqrt(x-1)) is x>1

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domain of f(x)=(sqrt(x+1))/(sqrt(x-1))

domain

f (x) = \frac{x + 1}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

f (x) = \frac{4}{x + 8}

y = 4 x

f (x) = \frac{x - 3}{x - 4}

y = \frac{x ^{2}}{1 + x ^{2}}

f (x) = \frac{x}{x ^{2} + 7}, - 6 \leq x \leq 0

What is the domain of f(x)=(sqrt(x+1))/(sqrt(x-1)) ?
The domain of f(x)=(sqrt(x+1))/(sqrt(x-1)) is x>1