What is the domain of y=(x^2)/(1+x^2) ?

The domain of y=(x^2)/(1+x^2) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=(x^2)/(1+x^2)

domain

y = \frac{x ^{2}}{1 + x ^{2}}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x}{x ^{2} + 7}, - 6 \leq x \leq 0

f (x) = x - 1 - x^{2}

f (x) = \frac{6}{x - 6}

y = \frac{6}{( 8 - x ) - 2}

+ sin (e^{t} - 1)

What is the domain of y=(x^2)/(1+x^2) ?
The domain of y=(x^2)/(1+x^2) is -infinity <x<infinity