What is the domain of y= 6/((sqrt(8-x))-2) ?

The domain of y= 6/((sqrt(8-x))-2) is x<4\lor 4<x<= 8

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domain of y= 6/((sqrt(8-x))-2)

domain

y = \frac{6}{( 8 - x ) - 2}

x < 4 or 4 < x \leq 8

Interval Notation

(- \infty, 4) \cup (4, 8]

Solution steps

Find non-negative values for radicals:

x \leq 8

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

x < 4 or 4 < x \leq 8

+ sin (e^{t} - 1)

U (x) = 24 x - 2328

f (x) = \frac{x}{x ^{2} - 7 x + 12}

f (x) = 6 x^{3}

f (x) = ln (x^{2} + x - 6) + x^{2} + x - 2

What is the domain of y= 6/((sqrt(8-x))-2) ?
The domain of y= 6/((sqrt(8-x))-2) is x<4\lor 4<x<= 8