What is the domain of f(x)= 1/((x-6)(x+1)) ?

The domain of f(x)= 1/((x-6)(x+1)) is x 6

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domain of f(x)= 1/((x-6)(x+1))

domain

f (x) = \frac{1}{( x - 6 ) ( x + 1 )}

x < - 1 or - 1 < x < 6 or x > 6

Interval Notation

(- \infty, - 1) \cup (- 1, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 1

The function domain

x < - 1 or - 1 < x < 6 or x > 6

\frac{2}{x ^{4}} - 4

f (x) = 7 x^{5}

f (x) = \frac{3 x + 6}{x + 2}

f (x) = 4 x^{2} + 16 x + 17

f (x) = \frac{x ^{2} - 4}{x - 2}

What is the domain of f(x)= 1/((x-6)(x+1)) ?
The domain of f(x)= 1/((x-6)(x+1)) is x<-1\lor-1<x<6\lor x>6