What is the domain of ln(x)+1/(x^2-1) ?

The domain of ln(x)+1/(x^2-1) is 0 1

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domain of ln(x)+1/(x^2-1)

domain

ln (x) + \frac{1}{x ^{2} - 1}

0 < x < 1 or x > 1

Interval Notation

(0, 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x > 0

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

0 < x < 1 or x > 1

f (x) = 7 + ln (3 x + 1)

f (x) = \frac{x - 5}{x ^{2} - 16}

R (x) = \frac{( x + 5 )}{x ( x + 11 )}

f (x) = 2 (x - 6)^{2} - 3

f (x) = \frac{2 x}{1 + x}

What is the domain of ln(x)+1/(x^2-1) ?
The domain of ln(x)+1/(x^2-1) is 0<x<1\lor x>1