What is the domain of f(x)=sqrt((2x)/(1+x)) ?

The domain of f(x)=sqrt((2x)/(1+x)) is x = 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt((2x)/(1+x))

domain

f (x) = \frac{2 x}{1 + x}

x < - 1 or x \geq 0

Interval Notation

(- \infty, - 1) \cup [0, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x \geq 0

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x \geq 0

f (x) = \frac{2 x - 4}{x + 4}

y = x - 3

f (x) = \frac{6}{x ^{2} - 9}

- 2 + e^{3 x} (4 - 2 x)

What is the domain of f(x)=sqrt((2x)/(1+x)) ?
The domain of f(x)=sqrt((2x)/(1+x)) is x<-1\lor x>= 0