What is the domain of f(x)= 6/(x^2-9) ?

The domain of f(x)= 6/(x^2-9) is x 3

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domain of f(x)= 6/(x^2-9)

domain

f (x) = \frac{6}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

- 2 + e^{3 x} (4 - 2 x)

f (x) = \frac{4 x - 2}{x + 4}

y = (2 x)^{\frac{1}{3}} - 7

f (x) = \frac{ln ( 5 x )}{x}

f (x) = \frac{x ^{2} + 1}{x ^{2} + 5}

What is the domain of f(x)= 6/(x^2-9) ?
The domain of f(x)= 6/(x^2-9) is x<-3\lor-3<x<3\lor x>3