What is the domain of f(x)=sqrt(1+6/x) ?

The domain of f(x)=sqrt(1+6/x) is x 0

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domain of f(x)=sqrt(1+6/x)

domain

f (x) = 1 + \frac{6}{x}

x \leq - 6 or x > 0

Interval Notation

(- \infty, - 6] \cup (0, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x > 0

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

x \leq - 6 or x > 0

6 x - 9

f (x) = \frac{2 x + 3}{x [ x + 4 ] - x}

lo g_{6} (\frac{x - 8}{x})

x^{2} (x + 1)^{3} (x - 3)

\frac{1}{4 x - 1} - 1 - x^{2}

What is the domain of f(x)=sqrt(1+6/x) ?
The domain of f(x)=sqrt(1+6/x) is x<=-6\lor x>0